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Вопрос по математике:
При каких значениях параметра a уравнение (a+1)x^2-4ax+4(a-2)=0 имеет два различных неотрицательных корня.-
Автор:
amandawashington
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Должны выполняться такие условия:
(a+1)f(0)≥0
и
D>0
имеем:
(a+1)(a-2)≥0
16a^2-16(a+1)(a-2)>0
(a+1)(a-2)≥0
a+2>0
Поскольку в точке а=-1 уравнение будет линейным
Ответ: a∈(-2;-1)∪[2;∞)
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