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Вопрос по математике:
Знайдіть:
1) НСК (12; 18);
2) НСК (8; 16);
3) НСК (9; 14);
4) НСК (36; 48);
5) НСК (210; 350);
6) HCK(12; 15; 18).
Очень срочно❤️-
Автор:
strong
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Чтобы найти НОК нескольких чисел, надо разложить эти числа на простые множители и найти произведение всех простых множителей, взятых с наибольшим показателем степени.
1) 12 = 2² · 3; 18 = 2 · 3²
НОК (12 и 18) = 2² · 3² = 36 - наименьшее общее кратное
36 : 12 = 3; 36 : 18 = 2
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2) 8 = 2³; 16 = 2⁴
НОК (8 и 16) = 2⁴ = 16 - наименьшее общее кратное
16 : 8 = 2; 16 : 16 = 1
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3) 9 = 3²; 14 = 2 · 7
НОК (9 и 14) = 2 · 3² · 7 = 126 - наименьшее общее кратное
126 : 9 = 14; 126 : 14 = 9
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4) 36 = 2² · 3²; 48 = 2⁴ · 3
НОК (36 и 48) = 2⁴ · 3² = 144 - наименьшее общее кратное
144 : 36 = 4; 144 : 48 = 3
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5) 210 = 2 · 3 · 5 · 7; 350 = 2 · 5² · 7
НОК (210 и 350) = 2 · 3 · 5² · 7 = 1050 - наименьшее общее кратное
1050 : 210 = 5; 1050 : 350 = 3
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6) 12 = 2² · 3; 15 = 3 · 5; 18 = 2 · 3²
НОК (12; 15 и 18) = 2² · 3² · 5 = 180 - наименьшее общее кратное
180 : 12 = 15; 180 : 15 = 12; 180 : 18 = 10
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