Вопрос по математике:

Решите уравнения а) 1 целая 13/14x- 2 целых 2/3 = 1 целая 2/7 б) 2 целых 2/7*(1/3x + 1/15 )= 2,4

1 13/14x - 2 2/3 = 1 2/7;27/14х - 8/3 = 9/7;27/14х =9/7 + 8/3;27/14х = 27/21 + 56/21;27/14х = 83/21;х = 83/21 : 27/14;х = 83/21 * 14/27;х = 1162/567;Сократим на 7:х = 1162 : 7 / 567 : 7;х = 166/81;1 13/14 * 166/81 - 2 2/3 = 1 2/7;27/14 * 166/81 - 8/3 = 9/7;4482/1134 - 8/3 = 9/7;83/21 - 8/3 = 9/7;83/21 - 27/21 = 9/7;56/21 = 9/7;9/7 = 9/7.2 2/7 * (1/3x + 1/15) = 2,4;16/7 * 1/3х + 16/7 * 1/15 = 2,4;16/21х + 16/105 = 2,4;Представим 2,4 как неправильную дробь со знаменателем 105:16/21х = 252/105 - 16/105;16/21х = 236/105;х = 236/105 : 16/21;х = 236/105 * 21/16;х = 4956/1680;х=59/20;2 2/7 * (1/3 * 59/20 + 1/15) = 2,4;16/7 * 59/60 + 16/7 * 1/15 = 2,4;944/420 + 16/105 = 2,4;236/105 + 16/105 = 2,4;252/105 = 2,4;2,4 = 2,4.