Вопрос по математике:

укажите при каких значениях x функция f x имеет производную и найдите эту производную a)f(x)= 1/(^3√x) б)f(x)= 1/(^3√x^2)

f(х)\' = (х^2 - 3х + 1)’ = (х^2)’ – (3х)’ + (1)’ = 2 * х^(2 – 1) – 3 * х^(1 - 1) – 0 = 2х – 3.

f(х)\' = (3 – 2х + 4х^2 – 7х^3)’ = (3)’ – (2х)’ + (4х^2)’ – (7х^3)’ = 0 – 2 * х^(1 – 1) + 4 * 2 * х^(2 - 1) – 7 * 3 * х^(3 – 1) = -2 * х^0 + 8 * х^1 – 21 * х^2 = -2 + 8х – 21х^2.

f(х)\' = (х^5 + х^3 – х^2 – 1)’ = (х^5)’ + (х^3)’ – (х^2)’ – (1)’ = 5 * х^(5 – 1) + 3 * х^(3 – 1) – 2 * х^(2 – 1) – 0 = 5х^4 + 3х^2 – 2х.

f(х)\' = (-5х^2 – 13х + 6)’ = (-5х^2)’ – (13х)’ + (6)’ = -5 * 2 * х^(2 – 1) – 13 * х^(1 – 1) – 0 = -10х – 13.

f(х)\' = (х^5 + 20х^2)’ = (х^5)’ + (20х^2)’ = 5 * х^(5 – 1) + 20* х^(2 – 1) = 5 * х^4 + 20 * х^1 = 5х^4 + 20х.

f(х)\' = (-6х^2 – 13х + 9)’ = (-6х^2)’ – (13х)’ + (9)’ = -6 * 2 * х^(2 – 1) – 13 * х^(1 – 1) – 0 = -12х – 13.

f(х)\' = (х^2 – 5х + 9)’ = (х^2)’ – (5х)’ + (9)’ = 2 * х^(2 – 1) – 5 * х^(1 – 1) – 0 = 2х – 5.